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Letf(x)={{:(x+1,", "if xge0),(x-1,", ...

`Letf(x)={{:(x+1,", "if xge0),(x-1,", "if xlt0):}".Then prove that" lim_(xto0) f(x)` does not exist.

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To prove that the limit \( \lim_{x \to 0} f(x) \) does not exist for the given piecewise function \( f(x) \), we will evaluate the left-hand limit and the right-hand limit as \( x \) approaches 0. ### Step-by-Step Solution: 1. **Define the function**: The function is defined as: \[ f(x) = ...
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