`int_(0)^(1)(dx)/(e^(x)+e^(-x))`

Explanation

To solve the integral \( \int_{0}^{1} \frac{dx}{e^{x} + e^{-x}} \), we can follow these steps:

### Step 1: Rewrite the Denominator
We start by rewriting the denominator \( e^{x} + e^{-x} \). We can factor out \( e^{-x} \):
\[ e^{x} + e^{-x} = e^{-x}(e^{2x} + 1) \]
Thus, we can rewrite the integral as:
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