Prove that `1 < int_0^2((5-x)/(9-x^2))dx < 6/5 `

Explanation

To prove that \( 1 < \int_0^2 \frac{5 - x}{9 - x^2} \, dx < \frac{6}{5} \), we will follow these steps:

### Step 1: Define the function
Let
\[ f(x) = \frac{5 - x}{9 - x^2} \]

...