Find the equation of line passing through point (2,-5) which is
(i) parallel to the line 3x + 2y - 4 = 0
(ii) perpendicular to the line 3x + 2y - 4 =0

Explanation

To find the equation of the line passing through the point (2, -5) that is (i) parallel to the line \(3x + 2y - 4 = 0\) and (ii) perpendicular to the same line, we will follow these steps:

### Part (i): Finding the equation of the line parallel to \(3x + 2y - 4 = 0\)

1. **Identify the slope of the given line**:
The given line can be rewritten in slope-intercept form \(y = mx + b\).
\[
3x + 2y - 4 = 0 \implies 2y = -3x + 4 \implies y = -\frac{3}{2}x + 2
...