Home
Class 12
MATHS
Two consecutive sides of a parallelogram...

Two consecutive sides of a parallelogram are `4x+5y=0` and `7x+2y=0` . If the equation of one diagonal is `11 x=7y=9,` find the equation of the other diagonal.

Text Solution

AI Generated Solution

To find the equation of the other diagonal of the parallelogram given the equations of two consecutive sides and one diagonal, we can follow these steps: ### Step 1: Identify the equations of the sides and the diagonal The equations of the two consecutive sides of the parallelogram are: 1. \(4x + 5y = 0\) (let's call this Line 1) 2. \(7x + 2y = 0\) (let's call this Line 2) The equation of one diagonal is given as: ...
Promotional Banner

Topper's Solved these Questions

  • STRAIGHT LINES

    CENGAGE ENGLISH|Exercise EXAMPLE|12 Videos
  • STRAIGHT LINES

    CENGAGE ENGLISH|Exercise CONCEPT APPLICATION EXERCISE 2.1|23 Videos
  • STRAIGHT LINE

    CENGAGE ENGLISH|Exercise Multiple Correct Answers Type|8 Videos
  • THEORY OF EQUATIONS

    CENGAGE ENGLISH|Exercise JEE ADVANCED (Numerical Value Type )|1 Videos

Similar Questions

Explore conceptually related problems

Two consecutive sides of a parallelogram are 4x+5y=0 and 7x+2y=0. If the equation of one diagonal is 11 x+7y=9, Equation of other diagonal : (A) 11x + 7y =0 (B) 3x - 5y + 5 = 0 (C) 7x + 11y = 0 (D) x-y =0

Two adjacent sides of a parallelogram are 4x+5y=0 ,and 7x+2y=0 . If the equation of one diagonal is 11x+7y=9 Area of the parallelogram is

The two adjacent sides of parallelogram are y = 0 and y=sqrt3(x-1) . If equation of one diagonal is sqrt3y=(x+1) , then equation of other diagonal is

If the lines represented by 2x^2-5xy+2y^2=0 be the sides of a parallelogram and the line 5x+2y=1 be one of its diagonal. Find the equation of the other diagonal, and area of the parallelogram .

The sides AB and AD of a parallelogram ABCD are 2x-y+1=0 and x+3y-10=0 respectively and C is the point (-1, -2) . Find the equation of the diagonals AC.

Two sides of a rhombus lying in the first quadrant are given by 3x-4y=0 and 12 x-5y=0 . If the length of the longer diagonal is 12, then find the equations of the other two sides of the rhombus.

If the lines ax^2+2hxy+by^2=0 be two sides of a parallelogram and the line lx+my=1 be one of its diagonal, show that the equation of the other diagonal is y (bl-hm)=x(am-hl).

The equation of one diagonal of a square is 2x+y=6 and its one vertex is (4,3) . Find the equation of other diagonal.

Two sides of a rhombus lying in the first quadrant are given by 3x-4y=0a n d12 x-5y=0 . If the length of the longer diagonal is 12, then find the equations of the other two sides of the rhombus.

Two sides of a Rhombus ABCD are parallel to the lines x-y=5 and 7x-y=3 . The diagonals intersect at (2,1) then the equations of the diagonals are