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Find the equation of a line that has -y-...

Find the equation of a line that has -y-intercept 4 and is a perpendicular to the line joining `(2,-3)` and `(4,2)dot`

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Let m be the slope of the required line.
Since the required line is perpendicular to the line joining A(2,-3) and B(4,2), we have
` m xx "Slope of AB" =-1`
` " or " m xx (2+3)/(4-2)=-1`
` " or " m = -(2)/(5)`
The required line cuts-off an intercept of 4 on the y-axis, So, c=4.
Hence, the equation of the required line is
`y=-(2)/(5)x+4`
or 2x+5y-20=0
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