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if `P` is the length of perpendicular from origin to the line `x/a+y/b=1` then prove that `1/(a^2)+1/(b^2)=1/(p^2)`

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To prove that \( \frac{1}{a^2} + \frac{1}{b^2} = \frac{1}{p^2} \), where \( P \) is the length of the perpendicular from the origin to the line \( \frac{x}{a} + \frac{y}{b} = 1 \), we can follow these steps: ### Step 1: Rewrite the line equation The given line equation is: \[ \frac{x}{a} + \frac{y}{b} = 1 \] We can rewrite this in the standard form of a line \( Ax + By + C = 0 \): ...
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