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Find the least value of (x-1)^(2) + (y-2...

Find the least value of `(x-1)^(2) + (y-2)^(2)` under the condition 3x+4y -2 = 0.

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`(x-1)^(2) + (y-2)^(2)` is square of distances between the points A(1,2) and P(x,y), where P lies on the line 3x +4y-2=0.
Least value of `(x-1)^(2) + (y-2)^(2)`
=Square of shortest distance of point (1,2) from the line 3x + 4y-2=0
`=((|3(1)+4(2)-2|)/(sqrt(3^(2) +4^(2))))^(2) = (9)/(25)`
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