If `x + y = 0` is the angle bisector of the angle containing the point (1,0), for the line `3x + 4y + b = 0; 4x+3y + b =0, 4x + 3y-, b = 0` then

Explanation

To solve the problem, we need to find the values of \( b \) such that the line \( x + y = 0 \) is the angle bisector of the angle formed by the lines \( 3x + 4y + b = 0 \) and \( 4x + 3y - b = 0 \).

### Step-by-Step Solution:

1. **Identify the Lines**:
We have two lines:
- Line 1: \( 3x + 4y + b = 0 \)
- Line 2: \( 4x + 3y - b = 0 \)
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