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A rectangle PQRS has its side PQ parall...

A rectangle PQRS has its side PQ parallel to the line `y= mx` and vertices `P, Q`, and `S` on the lines `y= a, x=b`,and `x= - b`, respectively. Find the locus of the vertex ` R`.

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To find the locus of the vertex \( R \) of the rectangle \( PQRS \) with the given conditions, we can follow these steps: ### Step 1: Define the coordinates of the vertices Let the coordinates of the vertices be defined as follows: - \( P(x_1, a) \) where \( y = a \) - \( Q(b, y_1) \) where \( x = b \) - \( S(-b, y_2) \) where \( x = -b \) - \( R(h, k) \) where we need to find the locus. ...
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