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The incident ray is along the line 3x-4y...

The incident ray is along the line `3x-4y-3=0` and the reflected ray is along the line `24 x+7y+5=0.` Find the equation of mirrors.

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To find the equation of the mirrors given the incident ray and reflected ray, we will use the concept of angle bisectors. Here are the steps to solve the problem: ### Step 1: Identify the equations of the incident and reflected rays The incident ray is given by the equation: \[ 3x - 4y - 3 = 0 \] The reflected ray is given by the equation: \[ 24x + 7y + 5 = 0 \] ### Step 2: Write the equations in the standard form The equations are already in the standard form \( Ax + By + C = 0 \): - For the incident ray: \( A_1 = 3, B_1 = -4, C_1 = -3 \) - For the reflected ray: \( A_2 = 24, B_2 = 7, C_2 = 5 \) ### Step 3: Use the angle bisector formula The angle bisector of two lines can be found using the formula: \[ \frac{A_1x + B_1y + C_1}{\sqrt{A_1^2 + B_1^2}} = \pm \frac{A_2x + B_2y + C_2}{\sqrt{A_2^2 + B_2^2}} \] ### Step 4: Calculate the necessary components First, calculate the denominators: - For the incident ray: \[ \sqrt{A_1^2 + B_1^2} = \sqrt{3^2 + (-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \] - For the reflected ray: \[ \sqrt{A_2^2 + B_2^2} = \sqrt{24^2 + 7^2} = \sqrt{576 + 49} = \sqrt{625} = 25 \] ### Step 5: Set up the angle bisector equations Substituting into the angle bisector formula gives us: \[ \frac{3x - 4y - 3}{5} = \pm \frac{24x + 7y + 5}{25} \] ### Step 6: Solve for the positive case Taking the positive case: \[ \frac{3x - 4y - 3}{5} = \frac{24x + 7y + 5}{25} \] Cross-multiplying gives: \[ 25(3x - 4y - 3) = 5(24x + 7y + 5) \] Expanding both sides: \[ 75x - 100y - 75 = 120x + 35y + 25 \] Rearranging terms: \[ 75x - 120x - 100y - 35y - 75 - 25 = 0 \] This simplifies to: \[ -45x - 135y - 100 = 0 \] Dividing by -5: \[ 9x + 27y + 20 = 0 \] ### Step 7: Solve for the negative case Now, taking the negative case: \[ \frac{3x - 4y - 3}{5} = -\frac{24x + 7y + 5}{25} \] Cross-multiplying gives: \[ 25(3x - 4y - 3) = -5(24x + 7y + 5) \] Expanding both sides: \[ 75x - 100y - 75 = -120x - 35y - 25 \] Rearranging terms: \[ 75x + 120x - 100y + 35y - 75 + 25 = 0 \] This simplifies to: \[ 195x - 65y - 50 = 0 \] Dividing by 5: \[ 39x - 13y - 10 = 0 \] ### Final Result The equations of the mirrors (angle bisectors) are: 1. \( 9x + 27y + 20 = 0 \) 2. \( 39x - 13y - 10 = 0 \)

To find the equation of the mirrors given the incident ray and reflected ray, we will use the concept of angle bisectors. Here are the steps to solve the problem: ### Step 1: Identify the equations of the incident and reflected rays The incident ray is given by the equation: \[ 3x - 4y - 3 = 0 \] The reflected ray is given by the equation: \[ 24x + 7y + 5 = 0 \] ...
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