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In triangle A B C , the equation of the ...

In triangle `A B C` , the equation of the right bisectors of the sides `A B` and `A C` are `x+y=0` and `y-x=0` , respectively. If `A-=(5,7)` , then find the equation of side `B Cdot`

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The correct Answer is:
14y = 10x
B and C will be the images of A on y+x=0 and y-x=0 respectively. Thus,
`B-=(-7,-5),C-=(7,5)`
Hence, the equation of BC is
`y-5 = (-5-5)/(-7-7)(x-7)`
i.e., 14y = 10x
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