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Prove that the parallelogram formed by t...

Prove that the parallelogram formed by the lines `x/a+y/b=1,x/b+y/a=1,x/a+y/b=2a n dx/b+y/a=2` is a rhombus.

A

`(pi)/(4)`

B

`(pi)/(2)`

C

`(pi)/(3)`

D

`(pi)/(6)`

Text Solution

Verified by Experts

The correct Answer is:
B
Clearly, distance between the parallel lines `(x)/(a)+(y)/(b) = 1 " and " (x)/(a) + (y)/(b) = 2 " is same as the distance between the parallel lines "(x)/(b)+(y)/(a) = 1 " and " (x)/(b)+(y)/(b) = 2`.
Therefore, quadrilateral is rhombus.
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