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The equation of set of lines which are a...

The equation of set of lines which are at a constant distance 2 units from the origin is

A

x+y+2=0

B

x+y+4=0

C

`x "cos" alpha + y "sin" alpha = 2`

D

`x "cos" alpha + y "sin" alpha = (1)/(2)`

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The correct Answer is:
To find the equation of the set of lines that are at a constant distance of 2 units from the origin, we can use the concept of the distance of a line from a point. ### Step-by-Step Solution: 1. **Understanding the Distance from the Origin**: The distance \( P \) from the origin (0, 0) to a line can be expressed using the formula: \[ \text{Distance} = \frac{|Ax + By + C|}{\sqrt{A^2 + B^2}} \] where \( Ax + By + C = 0 \) is the equation of the line. 2. **Setting Up the Equation**: For lines at a constant distance \( P = 2 \) from the origin, we can set up the equation: \[ \frac{|C|}{\sqrt{A^2 + B^2}} = 2 \] This implies: \[ |C| = 2\sqrt{A^2 + B^2} \] 3. **General Form of the Line**: The general form of the line can be expressed as: \[ Ax + By + C = 0 \] We can express \( C \) in terms of \( A \) and \( B \): \[ C = \pm 2\sqrt{A^2 + B^2} \] 4. **Finding the Set of Lines**: Substituting \( C \) back into the line equation gives us: \[ Ax + By \pm 2\sqrt{A^2 + B^2} = 0 \] This represents two families of lines for each pair of \( A \) and \( B \). 5. **Final Equation**: Therefore, the equation of the set of lines that are at a constant distance of 2 units from the origin can be represented as: \[ Ax + By = \pm 2\sqrt{A^2 + B^2} \] where \( A \) and \( B \) can take any non-zero values.

To find the equation of the set of lines that are at a constant distance of 2 units from the origin, we can use the concept of the distance of a line from a point. ### Step-by-Step Solution: 1. **Understanding the Distance from the Origin**: The distance \( P \) from the origin (0, 0) to a line can be expressed using the formula: \[ \text{Distance} = \frac{|Ax + By + C|}{\sqrt{A^2 + B^2}} ...
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CENGAGE ENGLISH-STRAIGHT LINES-EXERCISE (SINGLE CORRECT ANSWER TYPE)
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  8. The line x/3+y/4=1 meets the y-axis and x-axis at A and B respectively...

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  9. The area of a parallelogram formed by the lines a x+-b x+-c=0 is (a) (...

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  10. One diagonal of a square is 3x-4y+8=0 and one vertex is (-1,1), then t...

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  11. In an isoceles triangle OAB , O is the origin and OA=OB=6 . The equati...

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  14. The straight lines 7x-2y+10=0 and 7x+2y-10=0form an isosceles triangle...

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  15. The equations of the sides of a triangle are x+y-5=0, x-y+1=0, and y-1...

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  16. The equations of the sided of a triangle are x+y-5=0,x-y+1=0, and x+y-...

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  18. Distance of origin from the line (1+sqrt3)y+(1-sqrt3)x=10 along the li...

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