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The line x/3+y/4=1 meets the y-axis and ...

The line `x/3+y/4=1` meets the y-axis and x-axis at A and B respectively. A square `A B C D` is constructed on the line segment `A B` away from the origin. The coordinates of the vertex of the square farthest from the origin are

A

7,3

B

4,7

C

6,4

D

3,8

Text Solution

Verified by Experts

The correct Answer is:
B


The coordinates of A are (0,4) and those of B are (3,0).
`BC=AB=sqrt(3^(2)+4^(2)) = 5`
`"or " BL=BC "sin" theta "and " CL=BC "cos" theta`
`"or " BL=5 xx (4)/(5) = 4 "and"`
`CL=5 xx (3)/(5) = 3`
Similarly, MD =4 and AM=3.
So, the coordinates of C are (OB+BL,CL) `-=(7,3)` and those of D are (MD, OA+AM) `-=(4,7)`.
The coordinates of the vertex farthest from the origin are (4,7).
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