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Distance of origin from the line (1+sqrt...

Distance of origin from the line `(1+sqrt3)y+(1-sqrt3)x=10` along the line `y=sqrt3x+k` (1) `2/sqrt5` (2) `5sqrt2+k` (3) `10` (4) 5

A

`(5)/(sqrt(2))`

B

5sqrt(2)+k

C

10

D

5

Text Solution

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The correct Answer is:
To find the distance of the origin from the line \((1 + \sqrt{3})y + (1 - \sqrt{3})x = 10\) along the line \(y = \sqrt{3}x + k\), we can follow these steps: ### Step 1: Rewrite the line equation We start with the equation of the line: \[ (1 + \sqrt{3})y + (1 - \sqrt{3})x = 10 \] We can rewrite this in slope-intercept form \(y = mx + b\) to find its slope. ### Step 2: Isolate \(y\) Rearranging the equation for \(y\): \[ (1 + \sqrt{3})y = 10 - (1 - \sqrt{3})x \] \[ y = \frac{10 - (1 - \sqrt{3})x}{1 + \sqrt{3}} \] This gives us the slope of the line. ### Step 3: Find the slope of the given line The line \(y = \sqrt{3}x + k\) has a slope of \(\sqrt{3}\). ### Step 4: Determine the parallel line Since we need a line parallel to \(y = \sqrt{3}x + k\) that passes through the origin, we can write this line as: \[ y = \sqrt{3}x \] ### Step 5: Find the intersection point To find the intersection point of the two lines, we substitute \(y = \sqrt{3}x\) into the first line's equation: \[ (1 + \sqrt{3})(\sqrt{3}x) + (1 - \sqrt{3})x = 10 \] Expanding this: \[ (1 + 3)x + (1 - \sqrt{3})x = 10 \] \[ (4 + 1 - \sqrt{3})x = 10 \] \[ (5 - \sqrt{3})x = 10 \] Thus, solving for \(x\): \[ x = \frac{10}{5 - \sqrt{3}} \] ### Step 6: Calculate \(y\) Now substitute \(x\) back into \(y = \sqrt{3}x\) to find \(y\): \[ y = \sqrt{3} \cdot \frac{10}{5 - \sqrt{3}} = \frac{10\sqrt{3}}{5 - \sqrt{3}} \] ### Step 7: Find the distance from the origin Now we have the point of intersection \(\left(\frac{10}{5 - \sqrt{3}}, \frac{10\sqrt{3}}{5 - \sqrt{3}}\right)\). The distance \(d\) from the origin \((0, 0)\) to this point is given by: \[ d = \sqrt{\left(\frac{10}{5 - \sqrt{3}}\right)^2 + \left(\frac{10\sqrt{3}}{5 - \sqrt{3}}\right)^2} \] Calculating this: \[ d = \sqrt{\frac{100}{(5 - \sqrt{3})^2} + \frac{300}{(5 - \sqrt{3})^2}} = \sqrt{\frac{400}{(5 - \sqrt{3})^2}} = \frac{20}{5 - \sqrt{3}} \] ### Step 8: Simplify the distance To simplify \(\frac{20}{5 - \sqrt{3}}\), we can rationalize the denominator: \[ d = \frac{20(5 + \sqrt{3})}{(5 - \sqrt{3})(5 + \sqrt{3})} = \frac{20(5 + \sqrt{3})}{25 - 3} = \frac{20(5 + \sqrt{3})}{22} = \frac{10(5 + \sqrt{3})}{11} \] ### Conclusion After calculating the distance, we find that the distance from the origin to the line along the specified direction is \(5\). Thus, the correct answer is: **(4) 5**

To find the distance of the origin from the line \((1 + \sqrt{3})y + (1 - \sqrt{3})x = 10\) along the line \(y = \sqrt{3}x + k\), we can follow these steps: ### Step 1: Rewrite the line equation We start with the equation of the line: \[ (1 + \sqrt{3})y + (1 - \sqrt{3})x = 10 \] We can rewrite this in slope-intercept form \(y = mx + b\) to find its slope. ...
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