The area enclosed by `2|x|+3|y| le 6` is

Options

A. 3 sq. units
B. 4 sq. units
C. 12 sq. units
D. 24 sq. units

Explanation

To find the area enclosed by the inequality \(2|x| + 3|y| \leq 6\), we will follow these steps:

### Step 1: Rewrite the inequality
We start with the inequality:
\[ 2|x| + 3|y| \leq 6 \]
Dividing the entire inequality by 6 gives:
\[ \frac{|x|}{3} + \frac{|y|}{2} \leq 1 \]