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If the quadrilateral formed by the lines...

If the quadrilateral formed by the lines `a x+b y+c=0,a^(prime)x+b^(prime)y+c=0,a x+b y+c^(prime)=0,a^(prime)x+b^(prime)y+c^(prime)=0` has perpendicular diagonals, then `b^2+c^2=b^('2)+c^('2)` `c^2+a^2=c^('2)+a^('2)` `a^2+b^2=a^('2)+b^('2)` (d) none of these

A

`b^(2)+c^(2) = b^(2)+c^(2)`

B

`c^(2) +a^(2) = c'^(2) + a'^(2)`

C

`a^(2) + b^(2) = a'^(2) + b'^(2)`

D

none of these

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The correct Answer is:
To solve the problem, we need to analyze the conditions under which the quadrilateral formed by the given lines has perpendicular diagonals. The lines are: 1. \( ax + by + c = 0 \) 2. \( a'x + b'y + c = 0 \) 3. \( ax + by + c' = 0 \) 4. \( a'x + b'y + c' = 0 \) ### Step 1: Understanding the condition of perpendicular diagonals For a quadrilateral to have perpendicular diagonals, it can be shown that the product of the slopes of the diagonals must equal -1. However, in this case, we can also use the property of the distances between parallel lines. ### Step 2: Finding the distance between parallel lines The distance \( d \) between two parallel lines of the form \( Ax + By + C_1 = 0 \) and \( Ax + By + C_2 = 0 \) is given by the formula: \[ d = \frac{|C_2 - C_1|}{\sqrt{A^2 + B^2}} \] ### Step 3: Calculate distances for the given lines For the lines \( ax + by + c = 0 \) and \( ax + by + c' = 0 \): - The distance \( d_1 \) is: \[ d_1 = \frac{|c' - c|}{\sqrt{a^2 + b^2}} \] For the lines \( a'x + b'y + c = 0 \) and \( a'x + b'y + c' = 0 \): - The distance \( d_2 \) is: \[ d_2 = \frac{|c' - c|}{\sqrt{a'^2 + b'^2}} \] ### Step 4: Setting the distances equal Since the diagonals are perpendicular, the distances must be equal, so we set \( d_1 = d_2 \): \[ \frac{|c' - c|}{\sqrt{a^2 + b^2}} = \frac{|c' - c|}{\sqrt{a'^2 + b'^2}} \] Assuming \( |c' - c| \neq 0 \), we can cancel it from both sides: \[ \frac{1}{\sqrt{a^2 + b^2}} = \frac{1}{\sqrt{a'^2 + b'^2}} \] ### Step 5: Squaring both sides Squaring both sides gives: \[ a^2 + b^2 = a'^2 + b'^2 \] ### Conclusion Thus, we have shown that: \[ a^2 + b^2 = a'^2 + b'^2 \] This corresponds to option (c). ### Final Answer The correct option is: **(c) \( a^2 + b^2 = a'^2 + b'^2 \)**

To solve the problem, we need to analyze the conditions under which the quadrilateral formed by the given lines has perpendicular diagonals. The lines are: 1. \( ax + by + c = 0 \) 2. \( a'x + b'y + c = 0 \) 3. \( ax + by + c' = 0 \) 4. \( a'x + b'y + c' = 0 \) ### Step 1: Understanding the condition of perpendicular diagonals ...
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CENGAGE ENGLISH-STRAIGHT LINES-EXERCISE (SINGLE CORRECT ANSWER TYPE)
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  12. If a pair of perpendicular straight lines drawn through the origin ...

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  14. If AD, BE and CF are the altitudes of Delta ABC whose vertex A is (-4,...

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  15. The vertex A of DeltaABC is (3,-1). The equation of median BE and angl...

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  16. Suppose A, B are two points on 2x-y+3=0 and P(1,2) is such that PA=PB....

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  17. Triangle formed by variable lines (a+b)x+(a-b)y-2ab=0 and (a-b)x+(a+b)...

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  18. A light ray coming along the line 3x+4y=5 gets reflected from the line...

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