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The sides of a triangle are the straight lines `x+y=1,7y=x ,` and `sqrt(3)y+x=0` . Then which of the following is an interior point of the triangle? Circumcenter (b) Centroid Incenter (d) Orthocenter

A

Circumcenter

B

Centroid

C

Incenter

D

Orthocenter

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To determine which of the given points (circumcenter, centroid, incenter, orthocenter) is an interior point of the triangle formed by the lines \(x + y = 1\), \(7y = x\), and \(\sqrt{3}y + x = 0\), we will follow these steps: ### Step 1: Find the points of intersection of the lines We need to find the vertices of the triangle by determining the intersections of the three lines. 1. **Intersection of \(x + y = 1\) and \(7y = x\)**: - Substitute \(x = 7y\) into \(x + y = 1\): \[ 7y + y = 1 \implies 8y = 1 \implies y = \frac{1}{8} \] - Now, substituting \(y = \frac{1}{8}\) back to find \(x\): \[ x = 7 \cdot \frac{1}{8} = \frac{7}{8} \] - So, the first vertex is \(A\left(\frac{7}{8}, \frac{1}{8}\right)\). 2. **Intersection of \(x + y = 1\) and \(\sqrt{3}y + x = 0\)**: - Substitute \(x = -\sqrt{3}y\) into \(x + y = 1\): \[ -\sqrt{3}y + y = 1 \implies (1 - \sqrt{3})y = 1 \implies y = \frac{1}{1 - \sqrt{3}} \] - Now, substituting \(y\) back to find \(x\): \[ x = -\sqrt{3} \cdot \frac{1}{1 - \sqrt{3}} = \frac{-\sqrt{3}}{1 - \sqrt{3}} \] - The second vertex is \(B\left(\frac{-\sqrt{3}}{1 - \sqrt{3}}, \frac{1}{1 - \sqrt{3}}\right)\). 3. **Intersection of \(7y = x\) and \(\sqrt{3}y + x = 0\)**: - Substitute \(x = 7y\) into \(\sqrt{3}y + x = 0\): \[ \sqrt{3}y + 7y = 0 \implies (\sqrt{3} + 7)y = 0 \implies y = 0 \] - Now, substituting \(y = 0\) back to find \(x\): \[ x = 7 \cdot 0 = 0 \] - The third vertex is \(C(0, 0)\). ### Step 2: Identify the type of triangle The vertices of the triangle are \(A\left(\frac{7}{8}, \frac{1}{8}\right)\), \(B\left(\frac{-\sqrt{3}}{1 - \sqrt{3}}, \frac{1}{1 - \sqrt{3}}\right)\), and \(C(0, 0)\). To determine the type of triangle, we can check the lengths of the sides using the distance formula: - Length \(AB\), \(AC\), and \(BC\) can be calculated, but we can also analyze the slopes to determine if the triangle is obtuse. ### Step 3: Determine the location of the centers 1. **Circumcenter**: In an obtuse triangle, the circumcenter lies outside the triangle. 2. **Centroid**: The centroid is always inside the triangle. 3. **Incenter**: The incenter is also always inside the triangle. 4. **Orthocenter**: In an obtuse triangle, the orthocenter lies outside the triangle. ### Conclusion Since the circumcenter and orthocenter lie outside the triangle, and the centroid and incenter lie inside the triangle, the correct options for interior points of the triangle are: - **Centroid** - **Incenter** ### Final Answer The interior points of the triangle are: - (b) Centroid - (c) Incenter

To determine which of the given points (circumcenter, centroid, incenter, orthocenter) is an interior point of the triangle formed by the lines \(x + y = 1\), \(7y = x\), and \(\sqrt{3}y + x = 0\), we will follow these steps: ### Step 1: Find the points of intersection of the lines We need to find the vertices of the triangle by determining the intersections of the three lines. 1. **Intersection of \(x + y = 1\) and \(7y = x\)**: - Substitute \(x = 7y\) into \(x + y = 1\): \[ ...
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CENGAGE ENGLISH-STRAIGHT LINES-EXERCISE (MULTIPLE CORRECT ANSWERS TYPE)
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  2. The equation of the lines passing through the point (1,0) and at a dis...

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  3. The sides of a triangle are the straight lines x+y=1,7y=x , and sqrt(3...

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  4. If the straight line a x+c y=2b , where a , b , c >0, makes a triangle...

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  6. Equation(s) of the straight line(s), inclined at 30^0 to the x-axis su...

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  7. The lines x+y-1=0,(m-1)x+(m^2-7)y-5=0, and (m-2)x+(2m-5)y=0 are ...

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  8. The equation of a straight line passing through the point (2, 3) and ...

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  10. A line is drawn perpendicular to line y=5x , meeting the coordinate ax...

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  11. If x-2y+4=0a n d2x+y-5=0 are the sides of an isosceles triangle having...

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  12. Find the value of a for which the lines 2x+y-1=0, a x+3y-3=0, 3x...

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  13. The lines px +qy+r=0, qx + ry + p =0,rx + py+q=0, are concurrant then

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  14. theta1 and theta2 are the inclination of lines L1 and L2 with the x-ax...

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  15. Consider the lines L(1) -=3x-4y+2=0 " and " L(2)-=3y-4x-5=0. Now, choo...

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  16. The sides of a rhombus are parallel to the lines x+y-1=0 and 7x-y-5=0....

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  17. Two straight lines u=0a n dv=0 pass through the origin and the angle b...

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  18. Let u-=a x+b y+a b3=0,v-=b x-a y+b a3=0,a ,b in R , be two straight l...

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  19. Two sides of a triangle are parallel to the coordinate axes. If the ...

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