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ABCD is a parallelogram. x + 2y = 3 and ...

ABCD is a parallelogram. x + 2y = 3 and 2x + y = 3 are the equations of the diagonals AC and BD respectively. AC = 4 units and area of parallelogram ABCD is 8 sq. units then The length of BC is equal to

A

`sqrt(232)//3`

B

`4sqrt(58)//9`

C

`3sqrt(58)//9`

D

`4sqrt(58)//9`

Text Solution

Verified by Experts

The correct Answer is:
A
`"cos" (pi-theta) = (AP^(2) + PB^(2)-AB^(2))/(2AP xx PB)`
`"or " -(4)/(5) = (4+(100//9)-AB^(2))/(2 xx 2 xx (10//3))`
`"or " Bc = (sqrt(232))/(3)`
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