If the foci of the ellipse `(x^2)/(16)+(y^2)/(b^2)=1`
and the hyperbola `(x^2)/(144)-(y^2)/(81)=1/(25)`
coincide, then find the value
Text Solution
AI Generated Solution
To solve the problem, we need to find the value of \( b \) such that the foci of the given ellipse and hyperbola coincide.
### Step-by-Step Solution:
1. **Identify the equations of the ellipse and hyperbola:**
- The ellipse is given by:
\[
\frac{x^2}{16} + \frac{y^2}{b^2} = 1
...