Find the equation of tangent to the conic `x^2-y^2-8x+2y+11=0` at `(2,1)`.
Text Solution
AI Generated Solution
To find the equation of the tangent to the conic \( x^2 - y^2 - 8x + 2y + 11 = 0 \) at the point \( (2, 1) \), we will follow these steps:
### Step 1: Differentiate the conic equation
We start with the given conic equation:
\[
x^2 - y^2 - 8x + 2y + 11 = 0
\]
We will differentiate this equation with respect to \( x \).
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