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Find the equation of tangent to the coni...

Find the equation of tangent to the conic `x^2-y^2-8x+2y+11=0` at `(2,1)`.

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To find the equation of the tangent to the conic \( x^2 - y^2 - 8x + 2y + 11 = 0 \) at the point \( (2, 1) \), we will follow these steps: ### Step 1: Differentiate the conic equation We start with the given conic equation: \[ x^2 - y^2 - 8x + 2y + 11 = 0 \] We will differentiate this equation with respect to \( x \). ...
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