Find the equation of normal to the hyperbola `3x^2-y^2=1`
having slope `1/3dot`
Text Solution
AI Generated Solution
To find the equation of the normal to the hyperbola \(3x^2 - y^2 = 1\) with a slope of \(\frac{1}{3}\), we can follow these steps:
### Step 1: Rewrite the hyperbola in standard form
The given hyperbola is \(3x^2 - y^2 = 1\). We can rewrite it in standard form:
\[
\frac{x^2}{\frac{1}{3}} - \frac{y^2}{1} = 1
\]
This shows that \(a^2 = \frac{1}{3}\) and \(b^2 = 1\).
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