Normal to a rectangular hyperbola at P meets the transverse axis at N. If foci of hyperbola are S and S', then find the value of `(SN)/(SP).`
Text Solution
AI Generated Solution
To solve the problem, we need to find the value of \(\frac{SN}{SP}\) where \(N\) is the point where the normal to the rectangular hyperbola at point \(P\) intersects the transverse axis, and \(S\) and \(S'\) are the foci of the hyperbola.
### Step-by-Step Solution:
1. **Understanding the Hyperbola**:
A rectangular hyperbola has the standard equation \(xy = c^2\). The foci of this hyperbola are located at \((\pm c\sqrt{2}, 0)\).
2. **Normal to the Hyperbola**:
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P is a point on the hyperbola (x^2)/(a^2)-(y^2)/(b^2)=1,N is the foot of the perpendicular from P on the transverse axis. The tangent to the hyperbola at P meets the transvers axis at Tdot If O is the center of the hyperbola, then find the value of O T×O Ndot
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P is a point on the hyperbola (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 , and N is the foot of the perpendicular from P on the transverse axis. The tantent to the hyperbola at P meets the transverse axis at T. If O is the centre of the hyperbola, then OT.ON is equal to
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