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(x-1)(y-2)=5 and (x-1)^2+(y+2)^2=r^2 int...

`(x-1)(y-2)=5` and `(x-1)^2+(y+2)^2=r^2` intersect at four points A, B, C, D and if centroid of `triangle ABC` lies on line `y = 3x-4` , then locus of D is

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To solve the problem step by step, we need to find the intersection points of the two given equations and then determine the locus of point D based on the conditions provided. ### Step 1: Rewrite the equations The two equations given are: 1. \((x-1)(y-2) = 5\) 2. \((x-1)^2 + (y+2)^2 = r^2\) ### Step 2: Solve for \(y\) in terms of \(x\) from the first equation ...
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