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If a tangent to the parabola y^2 = 4ax i...

If a tangent to the parabola `y^2 = 4ax` intersects the `x^2/a^2+y^2/b^2= 1` at `A `and `B`, then the locus of the point of intersection of tangents at `A` and `B` to the ellipse is

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To solve the problem step by step, we will derive the locus of the point of intersection of tangents at points A and B to the ellipse given the conditions of the problem. ### Step 1: Understand the equations The equations given are: 1. The parabola: \( y^2 = 4ax \) 2. The ellipse: \( \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \) ### Step 2: Write the equation of the tangent to the parabola The equation of the tangent to the parabola at a point can be expressed as: \[ y = mx + \frac{a}{m} \] or equivalently, \[ mx - y = -\frac{a}{m} \] ### Step 3: Identify the intersection points A and B Let the tangent to the parabola intersect the ellipse at points A and B. The coordinates of these points can be denoted as \( (x_1, y_1) \) and \( (x_2, y_2) \). ### Step 4: Use the ellipse equation Substituting the tangent line equation into the ellipse equation: \[ \frac{x^2}{a^2} + \frac{(mx + \frac{a}{m})^2}{b^2} = 1 \] This will yield a quadratic equation in \( x \). ### Step 5: Find the slope of the tangents at points A and B The slopes of the tangents at points A and B can be derived from the quadratic equation obtained in the previous step. Let the slopes be \( m_1 \) and \( m_2 \). ### Step 6: Find the intersection point of the tangents at A and B The intersection point of the tangents at points A and B can be found using the point-slope form of the tangent equations: \[ y - y_1 = m_1(x - x_1) \] \[ y - y_2 = m_2(x - x_2) \] Solving these two equations will give the coordinates of the intersection point. ### Step 7: Derive the locus Let the intersection point of the tangents be denoted as \( (h, k) \). We can express \( h \) and \( k \) in terms of \( m_1 \) and \( m_2 \) and eliminate the parameters to find the relationship between \( h \) and \( k \). ### Step 8: Final equation for the locus After manipulating the equations, we will arrive at the equation of the locus, which can be expressed in the form: \[ k^2 = -\frac{b^4}{a^3}h \] This represents the locus of the point of intersection of the tangents at points A and B to the ellipse. ### Final Answer The locus of the point of intersection of the tangents at points A and B to the ellipse is given by: \[ y^2 = -\frac{b^4}{a^3} x \]

To solve the problem step by step, we will derive the locus of the point of intersection of tangents at points A and B to the ellipse given the conditions of the problem. ### Step 1: Understand the equations The equations given are: 1. The parabola: \( y^2 = 4ax \) 2. The ellipse: \( \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \) ### Step 2: Write the equation of the tangent to the parabola ...
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