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The chord of contact of a point P w.r.t ...

The chord of contact of a point `P` w.r.t a hyperbola and its auxiliary circle are at right angle. Then the point `P` lies (a) on conjugate hyperbola (b) one of the directrix (c) one of the asymptotes (d) none of these

A

conjugate hyperbola

B

one of the directrix

C

asymptotes

D

none of these

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To solve the problem step by step, we will analyze the given conditions and derive the necessary equations to determine the location of point \( P \). ### Step 1: Understand the Equations of the Hyperbola and the Auxiliary Circle The standard equation of a hyperbola is given by: \[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \] The auxiliary circle of the hyperbola has the equation: \[ x^2 + y^2 = a^2 \] ### Step 2: Write the Chord of Contact for the Hyperbola For a point \( P(h, k) \), the chord of contact with respect to the hyperbola is given by: \[ \frac{hx}{a^2} - \frac{ky}{b^2} = 1 \] ### Step 3: Write the Chord of Contact for the Auxiliary Circle The chord of contact with respect to the auxiliary circle is given by: \[ \frac{hx}{a^2} + \frac{ky}{a^2} = 1 \] ### Step 4: Determine the Slopes of the Chords From the equations of the chords, we can express them in slope-intercept form to find their slopes. 1. For the hyperbola: \[ ky = \frac{b^2}{a^2}hx - b^2 \implies y = \frac{b^2}{a^2 k}hx - \frac{b^2}{k} \] The slope \( m_1 = \frac{b^2}{a^2 k}h \). 2. For the auxiliary circle: \[ ky = -\frac{h}{a^2}x + a^2 \implies y = -\frac{h}{a^2 k}x + \frac{a^2}{k} \] The slope \( m_2 = -\frac{h}{a^2 k} \). ### Step 5: Use the Condition of Perpendicularity Since the chords are at right angles, the product of their slopes must equal \(-1\): \[ m_1 \cdot m_2 = -1 \] Substituting the slopes: \[ \left(\frac{b^2}{a^2 k}h\right) \left(-\frac{h}{a^2 k}\right) = -1 \] This simplifies to: \[ -\frac{b^2 h^2}{a^4 k^2} = -1 \implies b^2 h^2 = a^4 k^2 \] ### Step 6: Rearranging the Equation Rearranging gives: \[ \frac{h^2}{a^2} - \frac{k^2}{b^2} = 0 \] This implies: \[ \frac{h^2}{a^2} = \frac{k^2}{b^2} \] ### Step 7: Identify the Locus of Point \( P \) The equation \( \frac{h^2}{a^2} - \frac{k^2}{b^2} = 0 \) can be rewritten as: \[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 0 \] This represents the asymptotes of the hyperbola. ### Conclusion Thus, the point \( P \) lies on one of the asymptotes of the hyperbola. ### Final Answer The correct option is (c) one of the asymptotes.

To solve the problem step by step, we will analyze the given conditions and derive the necessary equations to determine the location of point \( P \). ### Step 1: Understand the Equations of the Hyperbola and the Auxiliary Circle The standard equation of a hyperbola is given by: \[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \] The auxiliary circle of the hyperbola has the equation: ...
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  6. If x=9 is the chord of contact of the hyperbola x^2-y^2=9 then the equ...

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  7. If the tangent at point P(h, k) on the hyperbola (x^(2))/(a^(2))-(y^(2...

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  8. Let P(a sectheta, btantheta) and Q(asecphi , btanphi) (where theta+p...

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  10. Portion of asymptote of hyperbola x^2/a^2-y^2/b^2 = 1 (between centre ...

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  11. If the angle between the asymptotes of hyperbola (x^2)/(a^2)-(y^2)/(b^...

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  12. Let any double ordinate P N P ' of the hyperbola (x^2)/(25)-(y^2)/(16)...

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  13. For hyperbola whose center is at (1, 2) and the asymptotes are paralle...

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  14. The asymptotes of the hyperbola (x^(2))/(a(1)^(2))-(y^(2))/(b(1)^(2))=...

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  15. If S=0 is the equation of the hyperbola x^2+4x y+3y^2-4x+2y+1=0 , then...

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  16. If two distinct tangents can be drawn from the Point (alpha,2) on diff...

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  17. A hyperbola passes through (2,3) and has asymptotes 3x-4y+5=0 and 12 x...

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  18. From any point on the hyperbola (x^2)/(a^2)-(y^2)/(b^2)=1 , tangents a...

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  19. The combined equation of the asymptotes of the hyperbola 2x^2 + 5xy + ...

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