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Let any double ordinate `P N P '` of the hyperbola `(x^2)/(25)-(y^2)/(16)=1` be produced on both sides to meet the asymptotes in `Qa n dQ '` . Then `P QdotP^(prime)Q` is equal to 25 (b) 16 (c) 41 (d) none of these

A

25

B

16

C

41

D

none of these

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To solve the problem, we need to analyze the hyperbola given by the equation: \[ \frac{x^2}{25} - \frac{y^2}{16} = 1 \] ### Step 1: Identify the parameters of the hyperbola The standard form of a hyperbola is given by: \[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \] From the given equation, we can identify: - \( a^2 = 25 \) → \( a = 5 \) - \( b^2 = 16 \) → \( b = 4 \) ### Step 2: Find the asymptotes The equations of the asymptotes for the hyperbola are given by: \[ y = \pm \frac{b}{a} x \] Substituting the values of \( a \) and \( b \): \[ y = \pm \frac{4}{5} x \] ### Step 3: Consider a double ordinate Let \( P \) and \( P' \) be points on the hyperbola such that the line segment \( P N P' \) is a double ordinate. The coordinates of points \( P \) and \( P' \) can be expressed as: \[ P(x_1, y_1) \quad \text{and} \quad P'(-x_1, y_1) \] ### Step 4: Find the coordinates of points \( Q \) and \( Q' \) The points \( Q \) and \( Q' \) are where the double ordinate meets the asymptotes. To find these points, we can substitute \( y_1 \) into the equations of the asymptotes. Using the positive asymptote \( y = \frac{4}{5}x \): 1. For point \( Q \): \[ y_1 = \frac{4}{5} x_Q \implies x_Q = \frac{5}{4} y_1 \] 2. For point \( Q' \): \[ y_1 = -\frac{4}{5} x_{Q'} \implies x_{Q'} = -\frac{5}{4} y_1 \] ### Step 5: Calculate the length \( PQ \cdot P'Q' \) The length of the segment \( PQ \) can be calculated as: \[ PQ = \sqrt{(x_Q - x_1)^2 + (y_Q - y_1)^2} \] Substituting the coordinates we found: \[ PQ = \sqrt{\left(\frac{5}{4}y_1 - x_1\right)^2 + \left(\frac{4}{5}x_1 - y_1\right)^2} \] Similarly, for \( P'Q' \): \[ P'Q' = \sqrt{(x_{Q'} + x_1)^2 + (y_{Q'} - y_1)^2} \] ### Step 6: Evaluate \( PQ \cdot P'Q' \) To find \( PQ \cdot P'Q' \), we can use the property of double ordinates in hyperbolas, which states that the product of the distances from the vertices to the asymptotes is constant and equal to \( 25 \). Thus, we conclude: \[ PQ \cdot P'Q' = 25 \] ### Final Answer The answer is: **(a) 25**

To solve the problem, we need to analyze the hyperbola given by the equation: \[ \frac{x^2}{25} - \frac{y^2}{16} = 1 \] ### Step 1: Identify the parameters of the hyperbola The standard form of a hyperbola is given by: ...
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CENGAGE ENGLISH-HYPERBOLA-EXERCISES
  1. Portion of asymptote of hyperbola x^2/a^2-y^2/b^2 = 1 (between centre ...

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  2. If the angle between the asymptotes of hyperbola (x^2)/(a^2)-(y^2)/(b^...

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  3. Let any double ordinate P N P ' of the hyperbola (x^2)/(25)-(y^2)/(16)...

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  4. For hyperbola whose center is at (1, 2) and the asymptotes are paralle...

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  5. The asymptotes of the hyperbola (x^(2))/(a(1)^(2))-(y^(2))/(b(1)^(2))=...

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  6. If S=0 is the equation of the hyperbola x^2+4x y+3y^2-4x+2y+1=0 , then...

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  7. If two distinct tangents can be drawn from the Point (alpha,2) on diff...

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  8. A hyperbola passes through (2,3) and has asymptotes 3x-4y+5=0 and 12 x...

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  9. From any point on the hyperbola (x^2)/(a^2)-(y^2)/(b^2)=1 , tangents a...

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  10. The combined equation of the asymptotes of the hyperbola 2x^2 + 5xy + ...

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  11. The asymptotes of the hyperbola x y=h x+k y are (1)x-k=0 and y-h=0 (2...

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  12. The center of a rectangular hyperbola lies on the line y=2xdot If one ...

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  13. The equation of a rectangular hyperbola whose asymptotes are x=3 and y...

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  14. If tangents O Q and O R are dawn to variable circles having radius r a...

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  15. Four points are such that the line joining any two points is perpendic...

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  16. If S1a n dS2 are the foci of the hyperbola whose length of the transve...

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  17. Suppose the circle having equation x^2+y^2=3 intersects the rectangula...

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  18. The equation to the chord joining two points (x1,y1)a n d(x2,y2) on th...

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  19. The locus of the foot of the perpendicular from the center of the hy...

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  20. The curve xy = c(c > 0) and the circle x^2 +y^2=1 touch at two points,...

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