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Draw the graph of y = sin^(-1)2x" and "y...

Draw the graph of `y = sin^(-1)2x" and "y=sin^(-1)(x//2)" and compare with " y = sin^(-1)x`.

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To solve the problem of drawing the graphs of \( y = \sin^{-1}(2x) \), \( y = \sin^{-1}\left(\frac{x}{2}\right) \), and comparing them with \( y = \sin^{-1}(x) \), we will follow these steps: ### Step 1: Determine the Domain of Each Function 1. **For \( y = \sin^{-1}(2x) \)**: - The function is defined when \( -1 \leq 2x \leq 1 \). - Dividing the entire inequality by 2 gives \( -\frac{1}{2} \leq x \leq \frac{1}{2} \). 2. **For \( y = \sin^{-1}\left(\frac{x}{2}\right) \)**: ...
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