Home
Class 12
MATHS
One vertex of an equilateral triangle is...

One vertex of an equilateral triangle is `(2,2)` and its centroid is `(-2/sqrt3,2/sqrt3)` then length of its side is (a) `4sqrt(2)` (b) `4sqrt(3)` (c) `3sqrt(2)` (d) `5sqrt(2)`

A

`4sqrt(2)`

B

`4sqrt(3)`

C

`3sqrt(2)`

D

`5sqrt(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the length of the side of the equilateral triangle given one vertex and the centroid, we can follow these steps: ### Step 1: Identify the given points We have one vertex of the equilateral triangle at point \( A(2, 2) \) and the centroid at point \( G\left(-\frac{2}{\sqrt{3}}, \frac{2}{\sqrt{3}}\right) \). ### Step 2: Understand the properties of the centroid The centroid \( G \) of a triangle with vertices \( A(x_1, y_1) \), \( B(x_2, y_2) \), and \( C(x_3, y_3) \) is given by: \[ G = \left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3}\right) \] Since we know \( A(2, 2) \) and \( G\left(-\frac{2}{\sqrt{3}}, \frac{2}{\sqrt{3}}\right) \), we can set up equations to find the coordinates of points \( B \) and \( C \). ### Step 3: Set up equations for the centroid Let the coordinates of points \( B \) and \( C \) be \( B(x_2, y_2) \) and \( C(x_3, y_3) \). The equations for the centroid become: \[ -\frac{2}{\sqrt{3}} = \frac{2 + x_2 + x_3}{3} \] \[ \frac{2}{\sqrt{3}} = \frac{2 + y_2 + y_3}{3} \] ### Step 4: Solve for \( x_2 + x_3 \) and \( y_2 + y_3 \) From the first equation, we can multiply both sides by 3: \[ -2\sqrt{3} = 2 + x_2 + x_3 \implies x_2 + x_3 = -2\sqrt{3} - 2 \] From the second equation: \[ 2\sqrt{3} = 2 + y_2 + y_3 \implies y_2 + y_3 = 2\sqrt{3} - 2 \] ### Step 5: Use the properties of the equilateral triangle In an equilateral triangle, the distance from the centroid to any vertex is \( \frac{2}{3} \) the length of the median. The median can be calculated using the distance formula. The length of the median from vertex \( A \) to the midpoint \( M \) of side \( BC \) can be found using the coordinates of \( A \) and the midpoint \( M \). ### Step 6: Find the coordinates of the midpoint \( M \) The midpoint \( M \) of \( B \) and \( C \) is given by: \[ M\left(\frac{x_2 + x_3}{2}, \frac{y_2 + y_3}{2}\right) \] ### Step 7: Calculate the distance \( AG \) Using the distance formula: \[ AG = \sqrt{\left(2 + \frac{2}{\sqrt{3}}\right)^2 + \left(2 - \frac{2}{\sqrt{3}}\right)^2} \] ### Step 8: Calculate the length of the side The length of the side \( A \) can be calculated using the relationship between the centroid and the vertices: \[ \text{Length of side} = 3 \times AG \] ### Step 9: Final calculation After calculating \( AG \) and multiplying by 3, we find the length of the side of the triangle. ### Conclusion After performing all calculations, we find that the length of the side of the equilateral triangle is \( 4\sqrt{2} \).

To find the length of the side of the equilateral triangle given one vertex and the centroid, we can follow these steps: ### Step 1: Identify the given points We have one vertex of the equilateral triangle at point \( A(2, 2) \) and the centroid at point \( G\left(-\frac{2}{\sqrt{3}}, \frac{2}{\sqrt{3}}\right) \). ### Step 2: Understand the properties of the centroid The centroid \( G \) of a triangle with vertices \( A(x_1, y_1) \), \( B(x_2, y_2) \), and \( C(x_3, y_3) \) is given by: \[ ...
Promotional Banner

Topper's Solved these Questions

  • COORDINATE SYSYEM

    CENGAGE ENGLISH|Exercise Multiple correct|13 Videos
  • COORDINATE SYSYEM

    CENGAGE ENGLISH|Exercise Linked|10 Videos
  • COORDINATE SYSYEM

    CENGAGE ENGLISH|Exercise Concept applications 1.6|9 Videos
  • COORDINATE SYSTEM

    CENGAGE ENGLISH|Exercise Multiple Correct Answers Type|2 Videos
  • CROSS PRODUCTS

    CENGAGE ENGLISH|Exercise DPP 2.2|13 Videos

Similar Questions

Explore conceptually related problems

If the equation of base of an equilateral triangle is 2x-y=1 and the vertex is (-1,2), then the length of the sides of the triangle is (a) sqrt((20)/3) (b) 2/(sqrt(15)) (c) sqrt(8/(15)) (d) sqrt((15)/2)

If the equation of base of an equilateral triangle is 2x-y=1 and the vertex is (-1,2), then the length of the sides of the triangle is sqrt((20)/3) (b) 2/(sqrt(15)) sqrt(8/(15)) (d) sqrt((15)/2)

The area of an equilateral triangle is 4sqrt(3)\ c m^2dot\ The length of each of its side is (a)3 cm (b) 4 cm (c) 2sqrt(3)\ c m (d) (sqrt(3))/2\ c m

1/(sqrt(9)-\ sqrt(8)) is equal to: (a) 3+2sqrt(2) (b) 1/(3+2sqrt(2)) (c) 3-2sqrt(2) (d) 3/2-\ sqrt(2)

Consider the parabola whose focus is at (0,0) and tangent at vertex is x-y+1=0 The length of latus rectum is (a) 4sqrt(2) (b) 2sqrt(2) (c) 8sqrt(2) (d) 3sqrt(2)

The value of sqrt(3-2\ sqrt(2)) is (a) sqrt(2)-1 (b) sqrt(2)+1 (c) sqrt(3)-sqrt(2) (d) sqrt(3)+\ sqrt(2)

The rationalisation factor of sqrt(3) is (a) -sqrt(3) (b) 1/(sqrt(3)) (c) 2sqrt(3) (d) -2sqrt(3)

The centroid of an equilateral triangle is (0, 0). If two vertices of the triangle lie on x+y=2sqrt(2), then one of them will have its coordinates. (a) (sqrt(2)+sqrt(6),sqrt(2)-sqrt(6)) (b) (sqrt(2)+sqrt(3),sqrt(2)-sqrt(3)) (c) (sqrt(2)+sqrt(5),sqrt(2)-sqrt(5)) (d) none of these

The rationalisation factor of 2+sqrt(3) is (a) 2-sqrt(3) (b) sqrt(2)+3 (c) sqrt(2)-3 (d) sqrt(3)-2

The height of an equilateral triangle is sqrt(6)\ c mdot Its area is (a) 3sqrt(3)\ c m^2 (b) 2sqrt(3)\ c m^2 (c) 2sqrt(2)\ c m^2 (d) 6sqrt(2)\ c m^2

CENGAGE ENGLISH-COORDINATE SYSYEM -Exercises
  1. P and Q are points on the line joining A(-2,5) and B(3,1) such that A ...

    Text Solution

    |

  2. In triangle ABC, angle B is right angled, AC=2 and A(2,2), B(1,3) then...

    Text Solution

    |

  3. One vertex of an equilateral triangle is (2,2) and its centroid is (-2...

    Text Solution

    |

  4. ABCD is a rectangle with A(-1,2),B(3,7) and AB:BC=4:3. If P is the cen...

    Text Solution

    |

  5. If (2,-3), (6,-5) and (-2,1) are three consecutive verticies of a rohm...

    Text Solution

    |

  6. If poitns A(3,5) and B are equidistant from H(sqrt2,sqrt5) and B has r...

    Text Solution

    |

  7. Le n be the number of points having rational coordinates equidistant ...

    Text Solution

    |

  8. In a triangle ABC the sides BC=5, CA=4 and AB=3. If A(0,0) and the int...

    Text Solution

    |

  9. If A(0, 0), B(1, 0) and C(1/2,sqrt(3)/2) then the centre of the circle...

    Text Solution

    |

  10. Statement 1: If in a triangle, orthocentre, circumcentre and centroid ...

    Text Solution

    |

  11. Consider three points P = (-sin (beta-alpha), -cos beta), Q = (cos(bet...

    Text Solution

    |

  12. If two vertices of a triangle are (-2,3) and (5,-1) the orthocentre li...

    Text Solution

    |

  13. The vertices of a triangle are (p q ,1/(p q)),(p q)),(q r ,1/(q r)), a...

    Text Solution

    |

  14. If the vertices of a triangle are (sqrt(5,)0) , (sqrt(3),sqrt(2)) , an...

    Text Solution

    |

  15. Two vertices of a triangle are (4,-3) & (-2, 5). If the orthocentre o...

    Text Solution

    |

  16. In Delta ABC if the orthocentre is (1,2) and the circumcenter is (0,0)...

    Text Solution

    |

  17. A triangle A B C with vertices A(-1,0),B(-2,3/4), and C(-3,-7/6) has i...

    Text Solution

    |

  18. If a triangle A B C ,A-=(1,10), circumcenter -=(-1/3,2/3), and orthoce...

    Text Solution

    |

  19. In the DeltaABC, the coordinates of B are (0, 0), AB=2, /ABC=pi/3 and ...

    Text Solution

    |

  20. If the origin is shifted to the point ((a b)/(a-b),0) without rotation...

    Text Solution

    |