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A light ray emerging from the point sour...

A light ray emerging from the point source placed at `P(2,3)` is reflected at a point `Q` on the y-axis. It then passes through the point `R(5,10)dot` The coordinates of `Q` are (a) `(0,3)` (b) `(0,2)` (c) `(0,5)` (d) none of these

A

(0,3)

B

(0,2)

C

(0,5)

D

none of these

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To solve the problem, we need to find the coordinates of point \( Q \) on the y-axis where a light ray reflects. The light ray originates from point \( P(2, 3) \) and passes through point \( R(5, 10) \) after reflecting at point \( Q \). ### Step-by-Step Solution: 1. **Identify the Coordinates of Point Q**: Since point \( Q \) is on the y-axis, its x-coordinate is \( 0 \). We can denote the coordinates of \( Q \) as \( Q(0, a) \), where \( a \) is the unknown y-coordinate we need to find. 2. **Use the Concept of Reflection**: The angle of incidence is equal to the angle of reflection. This means we can set up a relationship between the slopes of the lines \( PQ \) and \( QR \). 3. **Calculate the Slope of Line PQ**: The slope of line \( PQ \) can be calculated using the coordinates of points \( P(2, 3) \) and \( Q(0, a) \): \[ \text{slope of } PQ = \frac{a - 3}{0 - 2} = \frac{a - 3}{-2} \] 4. **Calculate the Slope of Line QR**: The slope of line \( QR \) can be calculated using the coordinates of points \( Q(0, a) \) and \( R(5, 10) \): \[ \text{slope of } QR = \frac{10 - a}{5 - 0} = \frac{10 - a}{5} \] 5. **Set the Slopes Equal**: Since the angle of incidence equals the angle of reflection, we can set the absolute values of the slopes equal to each other: \[ \left| \frac{a - 3}{-2} \right| = \left| \frac{10 - a}{5} \right| \] This leads to two cases to consider: - Case 1: \( \frac{a - 3}{-2} = \frac{10 - a}{5} \) - Case 2: \( \frac{a - 3}{-2} = -\frac{10 - a}{5} \) 6. **Solve Case 1**: \[ 5(a - 3) = -2(10 - a) \] \[ 5a - 15 = -20 + 2a \] \[ 5a - 2a = -20 + 15 \] \[ 3a = -5 \implies a = \frac{-5}{3} \quad \text{(not valid as } a \text{ must be positive)} \] 7. **Solve Case 2**: \[ 5(a - 3) = 2(10 - a) \] \[ 5a - 15 = 20 - 2a \] \[ 5a + 2a = 20 + 15 \] \[ 7a = 35 \implies a = 5 \] 8. **Final Coordinates of Point Q**: Thus, the coordinates of point \( Q \) are \( (0, 5) \). ### Conclusion: The coordinates of point \( Q \) are \( (0, 5) \), which corresponds to option (c).

To solve the problem, we need to find the coordinates of point \( Q \) on the y-axis where a light ray reflects. The light ray originates from point \( P(2, 3) \) and passes through point \( R(5, 10) \) after reflecting at point \( Q \). ### Step-by-Step Solution: 1. **Identify the Coordinates of Point Q**: Since point \( Q \) is on the y-axis, its x-coordinate is \( 0 \). We can denote the coordinates of \( Q \) as \( Q(0, a) \), where \( a \) is the unknown y-coordinate we need to find. 2. **Use the Concept of Reflection**: ...
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