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A triangle ABC has vertices A(5, 1), B (...

A triangle ABC has vertices `A(5, 1), B (-1, -7) and C(1, 4)` respectively. L be the line mirror passing through C and parallel to AB and a light ray eliminating from point A goes along the direction of internal bisector of the angle A, which meets the mirror and BC at E, D respectively. If sum of the areas of `triangle ACE` and `triangle ABE` is `K` sq units then`(2K)/5-6` is

Text Solution

Verified by Experts

The correct Answer is:
37.5
`=(AD)/(DE)=(BD)/(DC)=(AB)/(AC)=2`
`therefore D-=((1)/(3),(1)/(3))` and `E-=(-2,0)`
Area of `Delta ACE+"Area of" DeltaABC`
`(25)/(2)+25=37.5` sq.units
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