A bag contains `n+1` coins. If is known that one of these coins shows heads on both sides, whereas the other coins are fair. One coin is selected at random and tossed. If the probability that toss results in heads is 7/12, then find the value of `ndot`

Explanation

To solve the problem step by step, we will use the information provided to find the value of \( n \).

### Step 1: Understand the Problem
We have a bag containing \( n + 1 \) coins. One of these coins is biased (shows heads on both sides), and the remaining \( n \) coins are fair (show heads on one side and tails on the other). We need to find the value of \( n \) given that the probability of tossing heads is \( \frac{7}{12} \).

### Step 2: Define Events
Let:
- \( E_1 \): the event that the selected coin is the unfair coin (both sides are heads).
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