Home
Class 12
MATHS
Let f: Rvec satisfying |f(x)|lt=x^2AAx i...

Let `f: Rvec` satisfying `|f(x)|lt=x^2AAx in R` be differentiable at `x=0.` The find `f^(prime)(0)dot`

Text Solution

AI Generated Solution

To solve the problem, we need to find the derivative of the function \( f \) at \( x = 0 \), given that \( |f(x)| \leq x^2 \) for all \( x \in \mathbb{R} \) and that \( f \) is differentiable at \( x = 0 \). ### Step-by-step Solution: 1. **Understanding the condition**: We know that \( |f(x)| \leq x^2 \). This implies that as \( x \) approaches \( 0 \), \( f(x) \) must also approach \( 0 \). Specifically, at \( x = 0 \): \[ |f(0)| \leq 0^2 = 0 \implies f(0) = 0. \] ...
Promotional Banner

Topper's Solved these Questions

  • DIFFERENTIATION

    CENGAGE ENGLISH|Exercise Solved Examples|28 Videos
  • DIFFERENTIATION

    CENGAGE ENGLISH|Exercise Concept Application 3.1|1 Videos
  • DIFFERENTIAL EQUATIONS

    CENGAGE ENGLISH|Exercise Matrix Match Type|5 Videos
  • DOT PRODUCT

    CENGAGE ENGLISH|Exercise DPP 2.1|15 Videos

Similar Questions

Explore conceptually related problems

Let f: R->R satisfying |f(x)|lt=x^2,AAx in R be differentiable at x=0. Then find f^(prime)(0)dot

Let f : R rarr R satisfying |f(x)|le x^(2), AA x in R , then show that f(x) is differentiable at x = 0.

A function f: R->R satisfies that equation f(x+y)=f(x)f(y) for all x ,\ y in R , f(x)!=0 . Suppose that the function f(x) is differentiable at x=0 and f^(prime)(0)=2 . Prove that f^(prime)(x)=2\ f(x) .

A function f: R->R satisfies that equation f(x+y)=f(x)f(y) for all x ,\ y in R , f(x)!=0 . Suppose that the function f(x) is differentiable at x=0 and f^(prime)(0)=2 . Prove that f^(prime)(x)=2\ f(x) .

Let f: R->R satisfying f((x+y)/k)=(f(x)+f(y))/k( k != 0,2) .Let f(x) be differentiable on R and f'(0) = a , then determine f(x) .

A function f: R->R satisfies the equation f(x+y)=f(x)f(y) for all x , y in R and f(x)!=0 for all x in Rdot If f(x) is differentiable at x=0a n df^(prime)(0)=2, then prove that f^(prime)(x)=2f(x)dot

Let f(x y)=f(x)f(y)AAx , y in Ra n df is differentiable at x=1 such that f^(prime)(1)=1. Also, f(1)!=0,f(2)=3. Then find f^(prime)(2)dot

Let f(x y)=f(x)f(y)AAx , y in Ra n df is differentiable at x=1 such that f^(prime)(1)=1. Also, f(1)!=0,f(2)=3. Then find f^(prime)(2)dot

Let f(x y)=f(x)f(y)AAx , y in Ra n df is differentiable at x=1 such that f^(prime)(1)=1. Also, f(1)!=0,f(2)=3. Then find f^(prime)(2)dot

Let f(x+y)=f(x)+f(y)+2x y-1 for all real x and y and f(x) be a differentiable function. If f^(prime)(0)=cosalpha, the prove that f(x)>0AAx in Rdot