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y=tan^(-1)((acosx-bsinx)/(bcosx+asinx)),...

`y=tan^(-1)((acosx-bsinx)/(bcosx+asinx)),w h e r e-pi/2-1`

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To solve the problem step by step, we will differentiate the given function: Given: \[ y = \tan^{-1} \left( \frac{a \cos x - b \sin x}{b \cos x + a \sin x} \right) \] ### Step 1: Rewrite the expression We can simplify the expression by dividing the numerator and denominator by \( b \cos x \): \[ ...
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