The slope of the tangent to the curve `(y-x^5)^2=x(1+x^2)^2` at the point `(1,3)` is.

Explanation

`(y-x^(5))^(2)=x(1+x^(2))^(2)`
Differentiating both sides w.r.t. x, we get
`2(y-x^(5))((dy)/(dx)-5x^(4))=1(1+x^(2))^(2)+(x)(2(1+x^(2))(2x))`
On putting x=1 , y =3 in above equation, we get
`(dy)/(dx)=8`