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"Find "(dy)/(dx)" for "y=sin(x^(2)+1)....

`"Find "(dy)/(dx)" for "y=sin(x^(2)+1).`

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To find \(\frac{dy}{dx}\) for the function \(y = \sin(x^2 + 1)\), we will use the chain rule of differentiation. Here’s a step-by-step solution: ### Step 1: Identify the inner function Let \(u = x^2 + 1\). Thus, we can rewrite \(y\) in terms of \(u\): \[ y = \sin(u) \] ...
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