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If y=(sin^(-1)x)/(sqrt(1-x^2)),t h e n((...

If `y=(sin^(-1)x)/(sqrt(1-x^2)),t h e n((1-x^2)dy)/(dx)` is equal to `x+y` (b) `1+x y` `1-x y` (d) `x y-2`

A

x+y

B

1+xy

C

1-xy

D

xy-2

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To solve the problem, we need to differentiate the function \( y = \frac{\sin^{-1} x}{\sqrt{1 - x^2}} \) and then find the expression for \( (1 - x^2) \frac{dy}{dx} \). ### Step-by-Step Solution: 1. **Define the function**: \[ y = \frac{\sin^{-1} x}{\sqrt{1 - x^2}} \] ...
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