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If y=(x^x)^x then (dy)/(dx) is...

If `y=(x^x)^x` then `(dy)/(dx)` is

A

`y[x^(x)(log ex)log x+x^(x)]`

B

`y[x^(x)(log ex)log x+x]`

C

`y[x^(x)(log ex)log x+x^(-1)]`

D

`y[x^(x)(log_(e)x)log x+x^(-1)]`

Text Solution

AI Generated Solution

To find \(\frac{dy}{dx}\) for the function \(y = (x^x)^x\), we can follow these steps: ### Step 1: Rewrite the function Start by rewriting the function: \[ y = (x^x)^x = x^{x^2} \] ...
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