`"Let "y=t^(10)+1 and x=t^(8)+1." Then "(d^(2)y)/(dx^(2))` is

Options

A. `(5)/(2)t`
B. `20t^(8)`
C. `(5)/(16t^(6))`
D. none of these

Explanation

To find \(\frac{d^2y}{dx^2}\) given \(y = t^{10} + 1\) and \(x = t^{8} + 1\), we will follow these steps:

### Step 1: Express \(t^2\) in terms of \(x\)
From the equation \(x = t^8 + 1\), we can isolate \(t^8\):

\[ t^8 = x - 1 \]
...