Home
Class 11
MATHS
Statement1: A component of vector vecb =...

Statement1: A component of vector `vecb = 4hati + 2hatj + 3hatk` in the direction perpendicular to the direction of vector `veca = hati + hatj +hatk is hati - hatj`
Statement 2: A component of vector in the direction of `veca = hati + hatj + hatk is 2hati + 2hatj + 2hatk`

A

(a) Both the statements are true and statement 2 is the correct explanation for statement 1.

B

(b) Both statements are true but statement 2 is not the correct explanation for statement 1.

C

(c) Statement 1 is true and Statement 2 is false

D

(d)Statement 1 is false and Statement 2 is true.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze both statements regarding the vectors given. ### Given: - Vector **b** = \(4\hat{i} + 2\hat{j} + 3\hat{k}\) - Vector **a** = \(\hat{i} + \hat{j} + \hat{k}\) - Perpendicular direction to **a** = \(\hat{i} - \hat{j}\) ### Step 1: Find the unit vector in the direction of vector **a**. The unit vector **a** (denoted as **â**) can be calculated as follows: \[ \text{Magnitude of } \vec{a} = |\vec{a}| = \sqrt{1^2 + 1^2 + 1^2} = \sqrt{3} \] \[ \hat{a} = \frac{\vec{a}}{|\vec{a}|} = \frac{\hat{i} + \hat{j} + \hat{k}}{\sqrt{3}} = \frac{1}{\sqrt{3}}(\hat{i} + \hat{j} + \hat{k}) \] ### Step 2: Find the component of vector **b** in the direction of vector **a**. The component of vector **b** in the direction of **a** can be calculated using the formula: \[ \text{Component of } \vec{b} \text{ in the direction of } \vec{a} = \left(\vec{b} \cdot \hat{a}\right) \hat{a} \] Calculating the dot product \(\vec{b} \cdot \hat{a}\): \[ \vec{b} \cdot \hat{a} = (4\hat{i} + 2\hat{j} + 3\hat{k}) \cdot \left(\frac{1}{\sqrt{3}}(\hat{i} + \hat{j} + \hat{k})\right) \] \[ = \frac{1}{\sqrt{3}}(4 \cdot 1 + 2 \cdot 1 + 3 \cdot 1) = \frac{1}{\sqrt{3}}(4 + 2 + 3) = \frac{9}{\sqrt{3}} = 3\sqrt{3} \] Now, the component of **b** in the direction of **a** is: \[ \text{Component of } \vec{b} \text{ in the direction of } \vec{a} = 3\sqrt{3} \cdot \hat{a} = 3\sqrt{3} \cdot \frac{1}{\sqrt{3}}(\hat{i} + \hat{j} + \hat{k}) = 3(\hat{i} + \hat{j} + \hat{k}) = 3\hat{i} + 3\hat{j} + 3\hat{k} \] ### Step 3: Analyze Statement 2 Statement 2 claims that the component of vector **b** in the direction of vector **a** is \(2\hat{i} + 2\hat{j} + 2\hat{k}\). We found it to be \(3\hat{i} + 3\hat{j} + 3\hat{k}\), so Statement 2 is **false**. ### Step 4: Find the component of vector **b** in the direction perpendicular to vector **a**. To find the component of **b** in the direction perpendicular to **a**, we can use the formula: \[ \text{Component of } \vec{b} \text{ perpendicular to } \vec{a} = \vec{b} - \text{Component of } \vec{b} \text{ in the direction of } \vec{a} \] Calculating this: \[ \text{Component of } \vec{b} \text{ perpendicular to } \vec{a} = \vec{b} - (3\hat{i} + 3\hat{j} + 3\hat{k}) \] \[ = (4\hat{i} + 2\hat{j} + 3\hat{k}) - (3\hat{i} + 3\hat{j} + 3\hat{k}) = (4 - 3)\hat{i} + (2 - 3)\hat{j} + (3 - 3)\hat{k} \] \[ = 1\hat{i} - 1\hat{j} + 0\hat{k} = \hat{i} - \hat{j} \] ### Step 5: Analyze Statement 1 Statement 1 claims that the component of vector **b** in the direction perpendicular to vector **a** is \(\hat{i} - \hat{j}\). We found it to be \(\hat{i} - \hat{j}\), so Statement 1 is **true**. ### Conclusion - **Statement 1**: True - **Statement 2**: False ### Final Answer Statement 1 is true, and Statement 2 is false. ---

To solve the problem, we need to analyze both statements regarding the vectors given. ### Given: - Vector **b** = \(4\hat{i} + 2\hat{j} + 3\hat{k}\) - Vector **a** = \(\hat{i} + \hat{j} + \hat{k}\) - Perpendicular direction to **a** = \(\hat{i} - \hat{j}\) ### Step 1: Find the unit vector in the direction of vector **a**. ...
Promotional Banner

Topper's Solved these Questions

  • DIFFERENT PRODUCTS OF VECTORS AND THEIR GEOMETRICAL APPLICATIONS

    CENGAGE ENGLISH|Exercise Comprehension type|27 Videos
  • DIFFERENT PRODUCTS OF VECTORS AND THEIR GEOMETRICAL APPLICATIONS

    CENGAGE ENGLISH|Exercise Martrix - match type|10 Videos
  • DIFFERENT PRODUCTS OF VECTORS AND THEIR GEOMETRICAL APPLICATIONS

    CENGAGE ENGLISH|Exercise Exercises MCQ|134 Videos
  • CONIC SECTIONS

    CENGAGE ENGLISH|Exercise All Questions|1344 Videos
  • LIMITS AND DERIVATIVES

    CENGAGE ENGLISH|Exercise All Questions|691 Videos

Similar Questions

Explore conceptually related problems

The component of hati in the direction of vector hati+hatj+2hatk is

Find a unit vector in the direction of vector vecA=(hati-2hatj+hatk)

Find the unit vector in the direction of the vector veca=hati+hatj+2hatk .

Find component of vector vec(a)=hati+hatj+3hatk in directions parallel to and perpendicular to vector vecb=hati+hatj .

Find a unit vector perpendicular to both the vectors. vecA = 3hati + hatj + 2hatk and vecB = 2hati - 2hatj + 4hatk .

Find the unit vector perpendicular to the two vectors hati+2hatj-hatk and 2hati+3hatj+hatk .

If veca = (-hati + hatj - hatk) and vecb = (2hati- 2hatj + 2hatk) then find the unit vector in the direction of (veca + vecb) .

find vecA xx vecB if vecA = hati - 2 hatj + 4 hatk and vecB = 3 hati - hatj + 2hatk

Find a unit vector perpendicular to the plane of two vectros. veca=hati-hatj+2hatk and vecb=2hati+3hatj-hatk

The projection of vector veca=2hati+3hatj+2hatk along vecb=hati+2hatj+1hatk is