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If int (cos4x+1)/(cotx-tanx)dx=Af(x)+B, ...

If `int (cos4x+1)/(cotx-tanx)dx=Af(x)+B,` then

A

`A= -(1)/(8)`

B

`B=(1)/(2)`

C

`f(x)` has fundamental period `(pi)/(2)`

D

`f(x)` is an odd function

Text Solution

Verified by Experts

The correct Answer is:
A, C
`int(cos^(2)2xsin 2x dx)/(cos 2x)=(1)/(2) int sin 4x dx= -(1)/(8)cos 4x+B`
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