In a `DeltaABC`, the median to the side BC is of length `1/sqrt(11-6sqrt3)` and it divides the `angleA` into angles `30^@` and `45@.` Find the length of the side BC.

Explanation

To solve the problem step by step, we will use the information given in the question about triangle \( ABC \) and the properties of medians and angles.

### Step 1: Understand the Triangle and Given Information
We have triangle \( ABC \) with median \( AD \) to side \( BC \). The length of median \( AD \) is given as \( \frac{1}{\sqrt{11 - 6\sqrt{3}}} \). The median divides angle \( A \) into two angles: \( 30^\circ \) and \( 45^\circ \).

### Step 2: Define the Length of Side \( BC \)
Let the length of side \( BC \) be \( a \). Since \( D \) is the midpoint of \( BC \), we have \( BD = DC = \frac{a}{2} \).

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