In a triangle ABC, `angle A = 60^(@) and b : c = (sqrt3 + 1) : 2`, then find the value of `(angle B - angle C)`

Explanation

To solve the problem step by step, we need to find the value of \( \angle B - \angle C \) in triangle \( ABC \) where \( \angle A = 60^\circ \) and the ratio \( b : c = (\sqrt{3} + 1) : 2 \).

### Step 1: Set up the known values
We know:
- \( \angle A = 60^\circ \)
- The ratio \( b : c = \sqrt{3} + 1 : 2 \)

Let \( b = k(\sqrt{3} + 1) \) and \( c = 2k \) for some positive constant \( k \).
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