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All complex numbers 'z' which satisfy th...

All complex numbers 'z' which satisfy the relation `|z-|z+1||=|z+|z-1||` on the complex plane lie on the

A

`y=x`

B

`y=-x`

C

circle `x^(2)+y^(2)=1`

D

line `x=0` or on a line segment joining `(-1,0) to `(1,0)`

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To solve the equation \( |z - |z + 1|| = |z + |z - 1|| \), we will break it down step by step. ### Step 1: Define the complex number Let \( z = x + yi \), where \( x \) and \( y \) are real numbers, and \( i \) is the imaginary unit. ### Step 2: Rewrite the equation We need to express \( |z + 1| \) and \( |z - 1| \): - \( |z + 1| = |(x + 1) + yi| = \sqrt{(x + 1)^2 + y^2} \) - \( |z - 1| = |(x - 1) + yi| = \sqrt{(x - 1)^2 + y^2} \) ### Step 3: Substitute into the equation Substituting these into the original equation gives: \[ |z - |z + 1|| = |z + |z - 1|| \] This translates to: \[ |x + yi - \sqrt{(x + 1)^2 + y^2}| = |x + yi + \sqrt{(x - 1)^2 + y^2}| \] ### Step 4: Analyze the absolute values The left side \( |z - |z + 1|| \) can be analyzed as: \[ |x + yi - \sqrt{(x + 1)^2 + y^2}| \] And the right side \( |z + |z - 1|| \) can be analyzed as: \[ |x + yi + \sqrt{(x - 1)^2 + y^2}| \] ### Step 5: Set up the conditions To satisfy the equation, we need to consider the geometric interpretation of the absolute values. The expression \( |z - a| \) represents the distance from the point \( z \) to the point \( a \) in the complex plane. ### Step 6: Geometric interpretation From the equation, we can interpret that the distances from \( z \) to the points \( |z + 1| \) and \( |z - 1| \) must be equal. This implies that \( z \) lies on the perpendicular bisector of the segment joining the points \( -1 \) and \( 1 \) on the real axis. ### Step 7: Conclusion The perpendicular bisector of the segment joining \( -1 \) and \( 1 \) is the imaginary axis, where \( x = 0 \). Thus, all complex numbers \( z \) satisfying the given relation lie on the line \( x = 0 \) in the complex plane. ### Final Answer The locus of all complex numbers \( z \) satisfying the relation is the imaginary axis. ---

To solve the equation \( |z - |z + 1|| = |z + |z - 1|| \), we will break it down step by step. ### Step 1: Define the complex number Let \( z = x + yi \), where \( x \) and \( y \) are real numbers, and \( i \) is the imaginary unit. ### Step 2: Rewrite the equation We need to express \( |z + 1| \) and \( |z - 1| \): - \( |z + 1| = |(x + 1) + yi| = \sqrt{(x + 1)^2 + y^2} \) ...
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