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Product of all the even divisors of N = ...

Product of all the even divisors of `N = 1000`, is

A

`2^(20)*5^(20)`

B

`2^(24)*5^(24)`

C

`64*10^(18)`

D

None of these

Text Solution

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The correct Answer is:
To find the product of all the even divisors of \( N = 1000 \), we will follow these steps: ### Step 1: Factorize \( N \) First, we need to factor \( N \): \[ N = 1000 = 10^3 = (2 \times 5)^3 = 2^3 \times 5^3 \] ### Step 2: Identify the even divisors Even divisors of \( N \) must include at least one factor of 2. The general form of the divisors of \( N \) can be expressed as: \[ d = 2^a \times 5^b \] where \( 1 \leq a \leq 3 \) (since we need at least one factor of 2 for even divisors) and \( 0 \leq b \leq 3 \). ### Step 3: List the possible values for \( a \) and \( b \) The possible values for \( a \) (the power of 2) are: - \( a = 1 \) - \( a = 2 \) - \( a = 3 \) The possible values for \( b \) (the power of 5) are: - \( b = 0 \) - \( b = 1 \) - \( b = 2 \) - \( b = 3 \) ### Step 4: Count the even divisors The total number of even divisors can be calculated as: \[ \text{Number of choices for } a = 3 \quad (\text{1, 2, or 3}) \] \[ \text{Number of choices for } b = 4 \quad (\text{0, 1, 2, or 3}) \] Thus, the total number of even divisors is: \[ 3 \times 4 = 12 \] ### Step 5: Calculate the product of all even divisors The product of all divisors of a number \( N \) is given by \( N^{t/2} \), where \( t \) is the total number of divisors. First, we need to find the total number of divisors of \( N \): \[ t = (3 + 1)(3 + 1) = 4 \times 4 = 16 \] Now, the product of all the divisors of \( N \) is: \[ N^{t/2} = 1000^{16/2} = 1000^8 \] ### Step 6: Find the product of even divisors Since half of the divisors are even, the product of the even divisors is: \[ \text{Product of even divisors} = \sqrt{N^{t}} = N^{t/2} \times \sqrt{N^{t/2}} = 1000^{8} \times 1000^{4} = 1000^{12} \] ### Step 7: Simplify \( 1000^{12} \) Now, we can simplify \( 1000^{12} \): \[ 1000 = 10^3 \Rightarrow 1000^{12} = (10^3)^{12} = 10^{36} \] ### Final Answer Thus, the product of all the even divisors of \( N = 1000 \) is: \[ \boxed{10^{36}} \]

To find the product of all the even divisors of \( N = 1000 \), we will follow these steps: ### Step 1: Factorize \( N \) First, we need to factor \( N \): \[ N = 1000 = 10^3 = (2 \times 5)^3 = 2^3 \times 5^3 \] ...
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