If the letters of the word MATHEMATICS are arranged arbitarily, th probability that C comes before E, E before H, H before I and I before S, is
A
`(1)/(75)`
B
`(1)/(24)`
C
`(1)/(120)`
D
`(1)/(720)`
Text Solution
Verified by Experts
The correct Answer is:
C
`(c )` The total number of arrangments is `(11!)/(2!2!2!)=(11!)/(8)` The number of arrangements in which `CE,H,I,S` appear in that order `"^(11)C_(5)(6!)/(2!2!2!)=(11!)/(8*5!)` `:.` Required Proability `=((11!)/(8*5!))/((11!)/(8))=(1)/(120)`
if letters of the word MATHEMATICS are arranged then the probability that C come before E,E before H ,H before I and I before S
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