Show that the relation R in the set R of real numbers, defined as `R={(a ,b): alt=b^2}`is neither reflexive nor symmetric nor transitive.

Explanation

To show that the relation \( R \) in the set of real numbers defined as \( R = \{(a, b) : a \leq b^2\} \) is neither reflexive, nor symmetric, nor transitive, we will analyze each property step by step.

### Step 1: Check for Reflexivity
A relation \( R \) is reflexive if for every element \( a \) in the set, the pair \( (a, a) \) is in \( R \). This means we need to check if \( a \leq a^2 \) holds for all real numbers \( a \).

- For \( a = 1 \):
\[
1 \leq 1^2 \implies 1 \leq 1 \quad \text{(True)}
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