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ABCD is a square of side l. A line paral...

ABCD is a square of side `l`. A line parallel to the diagonal BD at a distance 'x' from the vertex A cuts two adjacent sides. Express the area of the segment of the square with A at a vertex, as a function of x. Find this area at `x=1//sqrt(2)` and at `x=2`, when `l=2`.

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To solve the problem, we will follow these steps: ### Step 1: Understanding the Geometry We have a square ABCD with side length \( l \). The vertices are labeled as follows: - \( A(0, 0) \) - \( B(l, 0) \) - \( C(l, l) \) - \( D(0, l) \) ...
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