Find the range of the function `f(x)=3 sin (sqrt((pi^(2))/(16)-x^(2))).`

Explanation

To find the range of the function \( f(x) = 3 \sin\left(\sqrt{\frac{\pi^2}{16} - x^2}\right) \), we will follow these steps:

### Step 1: Determine the domain of the function
The function \( f(x) \) is defined as long as the expression inside the square root is non-negative. Therefore, we need to solve the inequality:

\[ \frac{\pi^2}{16} - x^2 \geq 0 \]
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